DXC Quants Ratio and Proportion Quiz 1

Explanation:

Total money = 20 + 40 = 60

In this question, the total money is given so we need to multiply the value of the coins in the ratio.

10 × 0.10 x + 8 × 0.25x + 9 × 0.50x = 60

x + 2x + 4.5x = 60

7.5 x = 60

x = 8

Number of 50 paise coins = 9 × 8 = 72

Explanation:

Let the number Alberto, Brian and Dominic be 12a , 15a and 25a respectively

Then from the question 12a + 15a + 25a  =   312.

a = \frac{312}{52} = 6

 

Required Ratio,

= \frac{15\times 6 - 12\times 6}{25\times6-15\times6} = \frac{3}{10}3

=3 : 10

Explanation:

Let the quantity of each drugs be ‘a’

Then quantity of nicotine after mixing is,

(\frac{2}{3}+\frac{3}{10}+\frac{4}{15}+\frac{11}{20})a

By solving this equation:

We get,

(\frac{91}{60})a

and quantity of heroine after mixing is

=(\frac{3}{5}+\frac{7}{10}+\frac{11}{15}+\frac{9}{20})a

By solving the equation:

=(\frac{149}{60})a

 

Required ratio of nicotine to heroine after mixing,

=(\frac{\frac{91}{60}a}{\frac{149}{60}a})= 91:149

Explanation:

Ratio of 1st and 2nd numbers = 3 : 4

Ratio of 2nd and 3rd numbers = 5 : 6

Let the 2nd number = 5x, third number = 6x

Product of 2nd and 3rd numbers = 4320

5x × 6x = 4320

x2 = 144

x = 12

2nd number = 60, 3rd number = 72,

=(\frac{60}{4}\times3)= 45

Sum of three numbers = 60 + 72 + 45 = 177

Explanation:

Let the cost price of one table = x Rs., the cost price of one chairs = y Rs.

According to the question,

2x + 3y = 2200 ....1

2y + 4x = 2400

2x + y = 1200 ....2

After solving these 2 equation,

x = 350 Rs. , y = 500 Rs.

Ratio = 500 : 350 = 10 : 7

Explanation:

Let the income of Kate in 2018 and 2017 be 3x and 5x respectively.

Let the income of Jennifer in 2018 and 2017 be 3y and 2y respectively

Since, the ratio of their income in the year 2017 was 5 : 4

5x : 2y = 5 : 4

2x = y

The sum of their incomes in 2018 is Rs. 10242

3x + 3y = 10, 242

9x = 10, 242

x = 1,138 and y = 2276

Jennifer’s income for the year 2017 = 2y = Rs. 4552

Answer: c.
Explanation:
Amount of Petrol poured into C from vessels A and B,
=2\times \frac{3}{5}+3\times \frac{2}{3}=\frac{16}{5}litres

Also, amount of Diesel poured into C from vessels A and B,
=5-\frac{16}{5}=\frac{9}{5}litres

Given, 5 litres representing 40% of the capacity of vessel C, vessel C has a capacity of,
=5\times \frac{5}{2} = 12.5 litres

To make the quantities of Diesel and Petrol same in the vessel C, quantity of Diesel to be added,
=\frac{16}{5}-\frac{9}{5}= \frac{7}{5} litres

Therefore, the required ratio is,
=\frac{\frac{7}{5}}{12.5}= \frac{14}{125}litres

Answer: a.
Explanation:
Let the score of the topper be T.
Total score of the 52 students = 52 × 85 = 4420
Total score of the remaining 47 students after scores of the best five performers are removed,
= 47 × 83 = 3901
Total score of the top five students = 4420 – 3901 = 519

T + (total score of the next 4 top scores) = 519
T is the maximum when the total score of the next 4 top scorers is minimum.

Total score of the next 4 top scorers has a minimum value of 80 + 81 + 82 + 83 = 326
(since all the top 5 scores are distinct) and the least is 80.

T has a maximum value of 519 – 326 = 193

 

Explanation:
Ratio of the number of coins of denominations Rs. 1 : Rs. 2 : Rs. 5 = 5 : 7 : 6
Let, the number of coins of Rs. 1, Rs. 2 and Rs. 5 in the bag be 5x, 7x and 6x.
Since, the total value of Rs. 1 coin in the bag is Rs. 15
So, the number of coins of Rs. 1 in a bag = 15
5x = 15 , ⇒ x = 3
Therefore, number of Rs. 5 coins in the bag
= 6x = 18
So, required value of Rs. 5 coins,
= 6 × 3 × 5 = Rs.90
Therefore, Harley is having the coins worth Rs 90.

Answer: a.
Explanation:
Let the children be P, Q, R and S and Mr Flynn be F
Chocolates with P : Q : R = 3 : 7 : 11
Let the number of chocolates be 3X, 7X and 11X
Total chocolates with three eldest children = 21X
Chocolate with F and S = 3 × 21X = 63X
Total chocolates = (21X + 63X) = 84X
Chocolate with F : (P + Q + R + S) = 3 : 4
Total 7 units of chocolate = 84 X
1 unit = 12X
Chocolate with F = 3 × 12X = 36X
Chocolate with S = (63X – 36X) = 27X
27 X = 81 → X=3
Total number of chocolates = 84X = 84 × 3 = 252