Infosys Divisibility Questions and Answers Quiz – 1

Since the given number is divible by 5,So 0 or 5 must come in place of * .But a number ending with 5 is never divisible by 8.Therefore 0 will be in units place

The number formed by the last 4 digit is 4 *0which becomes divisible by 8, if * is replaced by 4.

((2)²)¹¹ × 7 ⁵ × 11²=2²² × 7⁵× 11²

Total number of prime factors =22+5+2=29

n is divisible by 3, 5 and 12 it must a multiple of the lcm of 3, 5 and 12 which is 60.

n = 60 k

n + 60 is also divisible by 60 since

n + 60 = 60 k + 60 = 60(k + 1)

Video solution:

When n is divided by 8, the remainder is 3 may be written as

n = 8 k + 3

multiply all terms by 6

6 n = 6(8 k + 3) = 8(6k) + 18

Write 18 as 16 + 2 since 16 = 8 * 2.

= 8(6k) + 16 + 2

Factor 8 out.

= 8(6k + 2) + 2

The above indicates that if 6n is divided by 8, the remainder is 2. The answer is B.

We first expand (2n + 2)²

(2n + 2)² = 4n ² + 8 n + 4

Factor 4 out.

= 4(n ² + 2n + 1)

(2n + 2)² is divisible by 4 and the remainder is equal to 0. The answer is A.

divided by 5 yields a remainder equal to 3 is written as follows

n = 5 k + 3 , where k is an integer.

add 2 to both sides of the above equation to obtain

n + 2 = 5 k + 5 = 5(k + 1)

The above suggests that n + 2 divided by 5 yields a remainder equal to zero.

Video solution: