Qualcomm Network Theory Quiz-1

Y₁₁ = Z₂₂/∆z and ∆z=3-2=1 and Z₂₂ = 1. So on substituting we get Y₁₁= 1/1=1.

Y₁₂= -Z₁₂/∆z and ∆z=3-2=1 and Z₁₂ = 1. So on substituting we get Y₁₂=- 1/1=-1.

We have the relation Y₂₁=- Z₂₁/∆z. ∆z=3-2=1 and given Z₂₁ = 2. On substituting we get Y₂₁=- 2/1=-2.

The relation between Y₂₂ and Z₁₁ is Y₂₂= Z₁₁/∆z and ∆z=3-2=1 and given Z₁₁ = 3. On substituting we get Y₂₂= 3/1=3.

∆y is the determinant of y parameters. The value ∆y is (Y₁₁)(Y₂₂)-(Y₁₂)(Y₂₁). On substituting the values we get ∆y = (1)(3)-(-2)(-1)=1.

∆y is the determinant of y parameters and ∆z is the determinant of z parameters. And we obtained ∆y = 1 and ∆z = 1. So their product = (1) (1) = 1.

V₁=(Y₂₂/∆y)I₁-(Y₁₂/∆y)I₂. The relation between Z₁₁ and Y parameters is Z₁₁ = Y₂₂/∆y.

V₁=(Y₂₂/∆y)I₁-(Y₁₂/∆y)I₂. The relation between Z₁₂ and Y parameters is Z₁₂ = (-Y₁₂)/∆y.

V₂=(-Y₂₁/∆y)I₁+(Y₁₁/∆y)I₂. The relation between Z₂₁ and Y parameters is Z₂₁ = (-Y₂₁)/∆y.

V₂=(-Y₂₁/∆y)I₁+(Y₁₁/∆y)I₂. The relation between Z₂₂ and Y parameters is Z₂₂ = Y₁₁/∆y.