TCS NQT Quiz 1 Work and Time questions

work done by thomas in day=1/7
work done by other in a day=1/9
work done by both in a day=1/7 +1/9 =16/63
days required by both = 63/16 =3.9



Video solution:

1/x = 1/8 - (1/16 + 1/24)
so x=48

ans = 48 days



Video solution:

A can do the total work in 8 days, and B can do it in 6 days.
Let the total work be 24 units. Now capacities are
A = 24/8 = 3,
B = 24/6 = 4,
A + B + C = 24/3 = 8
So Capacity of C = 1 unit.
In two days C will do 2 units which is 2/24th part of the total work. So 1/12th part.



Video solution:

George one day work is (1/15)
Marks one day work is (1/10)
G+M=(1/15)+(1/10)=(1/6)
6 is the answer



Video solution:

babla 10 day------ now 30/10=3 unit per day
L.C.M = 30(total work they have to perform)
ashu 15 day------- 30/15=2 unit per day

so their ratios of work is 3:2
so babla will get (3/5)*5000=3000



Video solution:

one day work done by A=1/20
work done by A in 2 days=1/10
work done by A,B,C on 3rd day=1/10+1/10=1/5
1/5th of the work will be completed at the end of 3 days
the remaining work =1-1/5=4/5
1/5 of work is completed in 3 days
total work wiil be done in 3*5=15 days



Video solution:

total work done=4*8*5=160units
now work=2*160=320units
now,2 men work for 20days,let x be the hours.
therefore, 2*20*x=320
x=8 hours



Video solution:

Here, we see that george does (3/5)th of work in 9 days.
So, he will complete the work in 9*5/3 = 15 days.

After 9th day, Paul Comes to join him.
Work left to be done = 1 - 3/5 = 2/5

They both complete the work in 4 more days.
Since, it takes george 15 days to complete the work.
In one day, he will complete (1/15)th of work.
In 4 days, he will do (4/15)th of work.

Now, work done by paul in 4 days = 2/5 - 4/15 = 2/15
So,paul completes (2/15)th of work in 4 days.

Therefore, In one day he will complete 2/60 of work or 1/30 of work.
So, number of days taken by paul to complete the work is 30 days.



Video solution:

as per data.. Y=2/3x---- (1) and Z=(3/4)Y----(2)
and they all type the same time X+Y+Z=1----(3)
and from equations (1) and (2) substitute interms of Y in eq (3)
(3/2)Y+Y+(3/4)Y=1
=>(6Y+4Y+3Y)/4=1
=>13Y/4 =1
=>Y=4/13
therefore ans is Y=4/13



Video solution:

EFFICIENCY OF A AND C = 5:3 (RATIO OF WORK DONE AND EFFICIENCY IS JUST REVERSE)
RATIO OF WORK DONE = 3:5 (LET IT BE 3X : 5X)
GIVEN :DIFFERENCE BETWEEN A'S AND C'S WORK DONE IS 6 DAYS SO, 5X-3X=6, X=3;
SO, A DO WORK IN 3*3= 9 DAYS
C DO WHOLE WORK IN=5*3=15 DAYS
NOW RATIO OF WORK DONE OF B AND C IS 2:3 (LET IT BE 2X : 3X)
AS WE HAVE CALCULATED C'S TOTAL WORK DONE IN 15 DAYS SO, 3X=15 DAYS , X=5
THEN B'S TOTAL WORK DONE IS 2*5= 10 DAYS
NOW WE HAVE TOTAL WORK DONE BY A ,B AND C IN 9,10 AND 15 DAYS RESPECTIVELY
B ANC WORK FOR 2 DAYS MEANS (1/10 +1/15)*2=1/3
REMAINING WORK=1-1/3 = 2/3
A DO TOTAL WORK IN 9 DAYS SO, 2/3 WORK IS DONE IN (9*2/3)=6 DAYS



Video solution: