Quiz – 1

person=x
mother=y
x=\frac{1}{3}y

x+16=\frac{1}{2}(y+16)

\frac{1}{3}y+16=\frac{1}{2}(y+16)

\frac{2}{3}y+32=y+16

2y+96=3y+48

y=96-48

y=48

Let the present age of Geet=x and her daughter=y, then
x=8y ---(i)

and

(x+8)/(y+8)=10/3 or 3x -10y =56 ----(ii)
On substituting x=8y in (ii),

we have 3*8y - 10y =56, 14y=56 or y=4
Hence x=8y=8*4= 32

Let the present age of gentleman (G) and wife (W) be 4x and 3x resp.... thus after 4 yrs the ratio will be (4x+4)/(3x+4)=9:7.. on solving we get the value as x=8..i.e present ages are G=32,W=24... Now at the time of marriage the ratio will be : (32-y)/(24-y)=5:3  on solving we get y=12... Thus 12 yrs ago they got married.

Present age of suraj=S=6V
Present age of vijay =V=(Present of suraj )-20
V= S - 20
V= 6V - 20
-5V = -20
V=4, S= 6V = 6*4=24, So ans is 24. option (e)

ram: rahim=3:2
rahim:aman = 5:2
making ratios equal
for that
ram: rahim:aman
1)3:2: (?)
2)(?) : 5:2 now as rahim s age ratio increased from 2 to 5
so to get ram s age ratio respect to that is 7.5
so ram:aman = 7.5:2 = 15:4

let harshit be x yrs then haritika be 240/x.
2*(240/x)=4+x;
2*(240/x)-x=4; 480-x^2=4x; x^2 +4x-430=0; (x+24)(x-20)=0; x=20;
here haritika age =(240/20)=12 yrs

Let the daughter s age be x and father s age be 4x. So as per question, 4x + 5 = 3(x + 5). So x = 10. Hence present age of daughter is 10 years and present age of father is 40 years. So after 5 + 5 = 10 years, daughter age would be 20 years and father’s age would be 50 years. Hence father would be 50/20 = 2.5 times of daughter’s age.

Let Aman s present age be x Aman s age before 10 years = x - 10) Aman s age after 20 years = (x + 20) We are given that, Aman s age after 20 years (x + 20) is 10 times his age 10 years back (x – 10) Therefore, (x + 20) = 10 (x – 10) Solving the equation, we get x + 20 = 10x – 100 9x = 120, x = 13.3 years

Let age of Romi be y
Nisha is 15 years elder than Romi = (y + 15).

So Nisha s age 5 years ago = (y + 15 – 5).

Romi s age before 5 years = (y – 5)
5 years ago, Nisha is 3 times as old as Romi
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25 ⇒ y = 12.5
Romi\'s age = 12.5 years
Nisha\'s age = (y + 15) = (12.5 + 15) = 27.5 years.

We are given that age ratio of Honey: Piyush = 2: 3
Honey’s age = 2x and Piyush’s age = 3x
One year ago, their age was 2x and 3x.
Hence at present, Honey s age = 2x +1 and Piyush s age = 3x +1
After 5 years, Honey s age = (2x +1) + 5 = (2x + 6)
Piyush s age = (3x +1) + 5 = (3x + 6)
After 5 years, this ratio becomes 4: 5. Therefore,
(2x+6) / (3x+6) = 4/5
10x + 30 = 12x + 24 ⇒ x = 3
Piyush s present age = (3x + 1) = (3x 3 + 1) = 10 years
Honey s present age = (2x + 1) = (2x 3 + 1) = 7 years