Quiz 1

If selling price of two articles is same, one earning r% profit and other incurring r% loss, then there is a net LOSS given by r^{2}/100


The actual Selling Price is irrelevant.

Net Loss =\frac{5^{2}}{100}=0.25

Loss% = (20/10)2 = (2)2 = 4%

Total S.P = Rs. 24000

Total C.P = Rs. (100/96 × 24000) = Rs. 25000

Loss = Rs. 1000

Let C.P = Rs. X

X + X% of X = 75

X2 + 100 X – 7500 = 0 Or (X+ 150) (X - 50) = 0

X = 50 (neglecting X= - 150)

: C.P = Rs. X

425 – X = X – 355 (or )

2X = 780 or X= 390

2X + Y = 7000

X + 2Y = 9800

Solving (i) and (ii), we get Y = 4200

C.P of 120 reams = Rs. (120 × 80 + 280 + 72 + 120 × 0.4) = Rs. 10000

C.P of 1 ream = (10000/120) = Rs. (250/3)

S.P of 1 ream = Rs. (108/100 × 250/3) = Rs. 90

S.P = Rs. 54000,

Gain earned = 20%

C.P = Rs. (100/120 × 54000) = Rs. 45000

S.P = Rs. 45000 and loss = 10%

C.P = Rs. (100/90 × 45000) = Rs. 50000

C.P = Rs. X

S.P = Rs. (90/100 × X) = Rs. (9/10 X)

C.P = Rs. (80/100 × X) = Rs. (4X/5) Gain = 40%

New S.P = Rs. (140/100 × 4X/5)

= Rs.28/25 X – 9/10 X = 55 or X = 250

C.P of 200 kg of sugar = Rs. (80 × 6.75 + 120 × 8) = Rs. 1500

C.P of 1 kg = Rs. (1500/200) = Rs. 7.50

Gain required = 20%

S.P of 1 kg = (120% of Rs. 7.50)

= Rs. (120/100 × 7.50) = Rs. 9 per kg

S.P be Rs. X C.P paid by Subhash = Rs. 9X/10

S.P received by Subhash = Rs. (108% of Rs. X)

= Rs. 27X/25

Gain = Rs. (27X/25 – 9X/10)

= Rs. 9X/50

Gain = (9X/50 × 10/9X × 100)% = 20%