Quiz-1

Number of runs made by running = 110 - (3 x 4 + 8 x 6)

= 110 - (60) = 50.

Required percentage = \left ( \frac{50}{110}\times 100 \right )%=45\tfrac{5}{11}%

Suppose originally he had x bananas.

Then, (100 - 40)% of x = 420.
⇒ (60/100) × x = 420
⇒ \frac{420\times 100}{60}=700

A = xy/100

B = yx/100

∴ A=B

Total Income = Simple Interest earned in First Scheme + Simple Interest earned in Second Scheme

Let money invested in Scheme First is “X”. Therefore, money invested in Scheme Second is “120000-X”

20000 = (X*10*1) / 100 + {(120000-X) * 20 * 1} / 100

On solving this equation. x = 40000

Therefore, Amount invested in Scheme first is 40,000.

Let Original Price = 100P

Cost price for Nitin = 100P – 0.30 × 100P = 70P

Selling price for Nitin = 70P + 0.20 × 70P = 84P

Now, net Profit/loss on original Price = {(84P-100P) / 100P} × 100 = -16%

Therefore, he made a loss of 16 percent on the original price of the Hero Activa

Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 71 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69,71

Number of such number =15

∴ Required percentage = \left ( \frac{15}{70}\times 100 \right )%=21\ %

Draw a diagram with 9 parts. One part represents striped shirts. Out of the remaining 8 parts: 5 parts represent the printed shirts and 3 parts represent plain colored shirts.

Let the amount taxable purchases be Rs. x.

Then 6% of x = 30/100

⇒ x=\left ( \frac{30}{100}\times \frac{100}{6} \right )=5

Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70

Ornament contains gold=720*90/100=648 gm. So silver=720-648=72 gm.
If 'x' gm. of silver is added to make 19% silver, then
(72+x)/(720+x)=19/100
On solving, x=80

Let us assume that the maximum
marks for the examination is x.
36% of x = 113 + 85          ⇒ 36x/100 = 198
⇒ 36x = 19800                  ⇒ x = 19800/36
∴ x = 550 marks.