Quiz-1

Explanation:

Quantity of milk =		60 x \frac{2}{3}		litres = 40 litres.

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water =	\frac{40}{20+x}

Now,	\frac{40}{20+x}			=	1
					2

20 + x = 80

x = 60.

Quantity of water to be added = 60 litres.

let R , N, P be an investment of Aman Chandra, Ankit Bhardwaj and Akash Kumar respectively
Therefore , 2R=3N ( given twice the investment of Aman is equal to thrice the capital of Ankit) and
N = 4P

Now, ratio of investment of R:N:P = 3N/2 : N :N/4,        which is 6:4:1
∴ share of Ankit out of the profit of Rs 22275 = (4/11)×22275 = 8100 .

A started the bussiness with investment 10000 for 4 years, i.e. 48 months

B joined A after 6 months with investnemt 8000 for 3 years and 6 months, i.e 42 months

C joined them after another six months with an investment of 12000 for 3 years, i.e for 36 months

By taking the ratio of 3 of them, we get-
10000×48 : 8000×42 : 12000×36
=10:7:9

The profit is distributed in the ratio 10:7:9

Let the investment by Raj=100
Diksha=2×100,     & Manish=3*100

100 will get cancel as it is common
so 1:2:3
now,multiplying by month
12×1 : 2×6 : 3×4 =1:1:1
∴ Manish profit= (1/3) ×45000=15000

24:50 :: 102:x        ⇒ 24/50 = 102/x

⇒x = (102 × 50)/ 24 = 212.5

let Steward monthly sal=x
(1/8)×x=6500      ⇒ x=6500×8 = 52000(total 1 month sal),

but given there his yearly sal=12×52000= Rs. 624000(ans)

C's share = [C's ratio/ sum of ratios] * total amount
C's share = (5/10) * 1260
C's share = 630

total calls taken last month= 440+360+300=1100
%of calls taken by first manager = (440/1100)*100=40%
Now,in next month total calls are=1500
so (40% of 1500)i.e.600 calls the first manager will take.
so the increase in call from last month is
600 -440 = 160 (ans)

only band=85-60=25
only sports= 200-60=140
no of students who involved either in band or sports is 25+140+60=225.

Lets get there without the 8...

Let 'x' be the number of perons in the group and let 'y' be
amount per head which they have to pay.
Then xy = 2400.
or y = 2400/x
Since two friends have forget the purse, x-2 persons should share the total amount(2400).
If they share, they have to make an extra contribution of 100 Rs to pay up the bill
That is x-2 persons should pay y+100 each
or (x-2)(y+100) = 2400
or y+100 = 2400/(x-2)
or y = 2400/(x-2) - 100
Therefore we have got two equations namely,
y= 2400/x and y = 2400/(x-2) - 100
Comparing these two, we get
2400/x = 2400/(x-2) - 100
Solving this we get
x^2 - 2x -48 = 0
or (x-8) (x+6) = 0
or x = 8 or x = -6
Since 'x' denotes the number of persons, it should be positive.
So, x = 8.