Quiz-1

work done by A in 1 day = 1/8.
for 2 days its 1/4.
remaining work is 1-1/4=3/4.

25 % of work is done atlast be C.
thrfore it is 1/4.

work done by B = 3/4-1/4 = 1/2.
days for B to complete is (1/2) /(1/12) = 6

days for C to complete 1/4 of the job (1/4) /(1/16) = 4.

A takes 2 days , B takes 6 days and C takes 4 days.
total is 12 days.

a-8 days, b- 7 days, c- 6 days

(a+b+c)'s 3 days work= (1/8+1/7+1/6)
= 73/168

work done in 3 triplets of days=(2×73)/168
= 73/84

remaining work =(1-(73/84))
=11/84

now remaining work is done by (A+b)together= 11/84
1/8 + B =11/84
B = 11/84 - 1/8 =1/168

1/168 work done by b in (7×1/168)= 7/168 days

total time taken = 7 + 1/168= 7 ⁷/₁₆₈

A\'s one minute work = 1/40

B\'s one minute work = 1/45

(A+B)\'s one minute work = 1/40 + 1/45 = 85/40*45 = 17/360

so, (A+B)will do work together in 360/17 min = 21 3/17 minutes

21 min approx

A + B \'s 1 day work = 1/28
A + B + C \'s 1 day work = 1/21

1/28 + C= 1/21
C = 1/21 - 1/28
C = 1/84

So C alone finish the work alone in 84 days.

4m+6f= (1/8)
7m+3f= (1/10)
∴ f=76/4800
10 female work=10(76/4800)=76/480
days=480/76=120/19

Formula for work = \frac{\textrm{men}\times \textrm{days}\times \textrm{working hour}}{\textrm{work}}

∴ \frac{M_1\ D_1\ t_1}{W_1}=\frac{M_2\ D_2\ t_2}{W_2}
⇒ \frac{10\times 15\times 8}{200}=\frac{5\times 10\times 6}{x}
∴ x = 50

A can write 16/3 page is 1 hr
B\'s 1 hr work=8 pages
A+B \'s 1 hr work= 16/3+8= 40/3 pages

So both ll finish 110 pages in

110/40 * 3= 33/4= 8 1/4

Ans: 8 hrs 15 mins

50 hens --- 200 eggs ---- 2 days
50 hens --- 100 eggs ---- 1 day
1 hen --- 2 eggs ---- 1 day
20 hens --- 40 eggs ---- 1 day
So 20 hens can lay 40 eggs in 1 day
then 20 hens can lay 400 eggs in 10 days (40×10=400)

Taking LCM of 120 and 135 seconds we get 1080 seconds i.e. 18 minutes; they both meet every 18 minutes.
Now speed of A = 25 m/min and B = 200/9 m/min.
A will take 80 minutes to cover 2000 m and B will take 90 minutes for the same.
80 being the smaller value; 4×18 = 72.
Therefore. answer = 4 times.

Total work done till all worker left the work
= \frac{10\times 40}{60\times 40} + \frac{10\times 35}{60\times 40} + \frac{10\times 30}{60\times 40} + \frac{10\times 25}{60\times 40} + \frac{10\times 20}{60\times 40} + \frac{10\times 15}{60\times 40} + \frac{10\times 10}{60\times 40} + \frac{10\times 5}{60\times 40} + \frac{10\times 0}{60\times 40}
= \frac{3}{4}

i.e. at the end of 80 days, no person is there to do work and the total work done at the end of 80 days be 3/4.