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On this page, you’ll find Clocks Questions and Answers for practice. Go through this page to get all sample Clocks Questions with Solutions along with basic formulas that can be used to solve the Clocks Questions.
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1. In a particular year 10th of 10th month was a Sunday In the same year 8th of 8th month falls on which day of the week?
Tuesday
Wednesday
Saturday
Sunday
If 10th October is Sunday then 1st October is Friday. Now, September has 30 days which means it has 2 odd days (30/7) So, 1st of September will be Wednesday
Now August has 31 days but we need to calculate the 8th day
So, 31/7 gives 3 odd days
If 1st August is Sunday then 8th day of August will be also Sunday.
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2. A faulty watch gains 7 seconds in 4 minutes. After you woke up. you set the clock right at 9:00 AM. When you returned home from the office, you saw the clock showing 5:20 PM. What time did you return home?
5:25 PM
5:12 PM
5:15 PM
5: 05 PM
Now, let's calculate the time difference between when you set the clock right (9:00 AM) and when you returned home (5:20 PM).
Time difference = 5:20 PM - 9:00 AM
First, let's convert both times to 24-hour format for easier calculations.
5:20 PM in 24-hour format = 17:20 9:00 AM in 24-hour format = 9:00
Now, we can calculate the time difference:
Time difference = 17:20 - 9:00
Since we are dealing with time, we need to borrow 1 hour from the hours column:
Time difference = 8:20
Total hours in minutes = 500 minutes Gain in seconds = (500/4) * 7 = 875 So, Total extra minutes = 14.58 minutes
So, actual time = 5:05 pm (approx).
3. If a clock, set at 04:00 on 5th Feb 1772, gains 5 seconds every hour, What will be the angle(in degrees) in the middle of minute and the hour hand on 2nd March 1772 if the actual time is 4 PM.
155
156
157
147
The clock gains 5 seconds every hour
So in 1 day, i.e. 24 hours it gains 120 seconds
From February 5 to March 2, there are 27 days (as we are counting from 4’o clock to 4’o clock)
= 120*27
=3240 seconds
= 3240/60
= 54 minutes
This means the clock on 2nd March is running 54 minutes ahead of the actual time i.e. 4’o clock. So the current time is 4:54
60 minutes = 30 degrees
1 minute = 30/60 = 0.5 degrees
54 minutes = 54*0.5 = 27 degrees
At 4 the angle made by hour hand and the minute hand = 120 degrees
Therefore at 4:54 = 120+27 = 147 degrees
4. What would be the angle subtended in the middle of the hour portion and the minute portion when the watch shows 8:20 timing?
130 degree
120 degree
110 degree
None of these
For a sector, the angle subtended is 30 degrees.
So here are 4 sectors between the hour hand on 8 and minute hand on 20 i.e. 30 x 4 = 120 degrees.
5. On which day of the year will be 18th July, 1996?
Thursday
Friday
18th July, 1996 = (1995 years + duration between 1.1.1996 to 18.7.1996)
1600 years have 0 odd days
300 years have = (5 x 3) =1
95 years have 23 leap years in total plus 72 normal years.
Odd days in 95 years ( 23 * 2 + 72 *1 (odd day) = 118 = 118/7 gives 6 odd days.
200 days = (28 weeks + 4 odd day)
Total odd days = (0 + 1 + 6 + 4) = 11 days = 1 week and 4 odd days
4th day is Thursday.
6. Calculate the time (amid 3:00 and 4:00) when both the clock points are collected?
3: 16 4/11
3: 22
3: 51 2/3
3: 10
At 3:00 the hour needle would be on 3 and the minute hand would be on 12
Which meant there is a 15 minute space between them and to collide the minute needle should advance 15 mins. Above the hour needle.
Therefore 55 minutes will be advanced in 60/55 * 15 = 16 4/11 minutes
Hence the hands will coincide at 16 4/11 past 3
7. Calculate the time (amid 4:00 & 5:00) when both the hands of the needles form a right angle?
5: 05 5/11
5: 06
5: 04
5: 05 2/11
At 4:00 the minute needle will be 20 minutes apart from the hour needle. And to form a right angle, they will be 15 minutes apart
When the min. hand is 15 minute space behind the hour needle, and to come at this position the minute needle has to advance (20-15)= 5 minute space
Now it will take 60 mins. To advance or gain 55 minute space.
Therefore 5 min. space will be advanced in 60/55 *5 = 5 5/11 minutes
Therefore they will be at the right angle at past 5 5/11 min past 5
8. Calculate the time (between 8:00- 9:00) when the points of the clock will formulate a straight line without being together?
8:12 2/3
8: 09 10/11
8: 11 11/12
8: 10 10/11
At 8:00 hr. needle will be on 8 and the minute needle will be at 12 and both of them will be 20 minutes apart from each other. And to formulate a single straight line without being together the needles must be 30 minutes space away from each other. Hence the minute needle must gain (30-20= 10 Mins.) space above the hour needle.
So in 60 Minutes total 55 minutes are gained.
Hence to gain 10 mins. It will take 60/55*10 - 10 10/11 minutes
Therefore the needles will formulate a straight line without being together at 8 past 10 10/11 minutes
9. If the minute needle of the clock overtakes the hour needle every 65 minutes interval of the correct time, how much will the clock gain or lose?
10 10/143 minutes gain
9 1/13 minutes gain
12 12/13 minutes loss
None
If the clock runs correctly then the minute needle gets advanced by 55 minute over the hour needle in every 60 minutes. And to unite together the minute needle must advance 60 minutes above the hour needle.
Further since 55 minutes are extended in every 60 minutes
Therefore 60 minutes will be advanced in 65/55 *60 = 65 5/11 min.
But as per the question they are together after 65 minutes
Therefore gain in 65 minutes= 65 5/11 - 65 = 5/11
Gain in 24 hrs= 5/11 * (60+24)/65 = 10 10/143 minutes
10. If a clock gets 5 minutes slow at 8 O’ Clock on a Sunday morning and 5 min. 48 Sec. fast at 8:00 PM on the coming Sunday? Then find out when exactly was it showing the actual time?
Wednesday 7:20 PM
Tuesday 10:20 PM
Sunday 10:11 PM
Time between 8:00 Am on Sunday to 8:00 Pm on the coming Sunday= 7 days and 12 hrs= 180 hours.
Thus a watch gains 5 + 5 4/5 minutes or 54/5 minutes in 180 hrs
Now 54/5 min are gained in 180 hrs
Therefore 5 min. are advanced in 180*5/54 *5= 83 hrs 20 min or 3 days 11 hrs 20 min
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