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September 19, 2023
On this page we will be discussing about Pipes And Cistern Questions that are generally asked in placement Exams. Pipes and Cistern is a common topic asked in various companies exams. Two basic terminologies in Pipes and Cistern Topic are:
Time, Rate, and Volume Relationship:Time = Volume / RateRate = Volume / TimeVolume = Rate × Time
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1. There are 15 vessels of water with the volume of 60 litters each. Together they can fill the cistern completely. Calculate how many vessels will be required to completely fill the cistern if their volume is reduced to 20 liters.
40 vessels
45 vessels
42 vessels
35 vessels
Solution:
Total capacity of cistern = 60*15 = 900 liters
Total vessels needed to fill the cistern if the total volume of each vessel is reduces to 20 liters = 60*15 / 20 = 900/20 = 45 vessels
Correct answer B
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2. There are two pipes, Pipe M and Pipe N. They can fill a container respectively in 9 hours and 3 hours. Both Pipe M and Pipe N are opened alternatively in every hour and pipe N is started after pipe M. Identify in how many hours the container will be overflowed?
7 hr
5 hr
6 hr
4 hr
Container filled by pipe M in 1 hour = 1 / 9
Container filled by pipe N in 1 hour = 1 / 3
Container filled by both if open alternatively = 1/9 + 1/3 = 4/9 (in 2 hours)
Container filled by both in another 2 hours = 4/9 + 4/9 = 8/9
Remaining 1/9th part will be filled by pipe M in another one hour.
Total time = 2+2+1 = 5 hours
3. An electric pump is used for emptying and filling a storage chamber of water. The storage chamber contains 3200 liters of water. What is the filling capacity, if the emptying of the storage chamber is 20 liters/minute more than its filling capacity and the pump requires 8 minutes less to empty the storage chamber than it requires to fill it?
100
80
70
50
Let us assume the filling capacity of the pump be x liter/minute
The emptying capacity will be 20+x liter/minute
Time needed to fill the storage chamber = 3200 / x
Time needed to empty the storage chamber = 3200 / x+20
Given, the pump requires 8 minutes less in emptying the storage chamber,
= 3200/x – 3200/x+20 = 8
= 400/x – 400/x+20 = 1
= 400(x+20) – 400x = x(x+20)
= 400x + 8000 – 400x = x2 + 20x
= 8000 = x2 + 20x
= x2 + 20x – 8000 = 0
= (x + 100) (x - 80) = 0
x = -100, x = 80
Since liters cannot be negative, therefore the filling capacity is 80 liters/ minute.
4. Pipes A and B running together can fill a cistern in 6 minutes. If B takes 5 minutes more than A to fill the cistern, then what will be the respective times in which A and B will fill the cistern separately?
10 min and 12 minutes
10 min and 15 minutes
20 min and 10 minutes
16 min and 11 minutes
5. Due to an open outlet pipe a tank will tank 4 hours more to be filled. Normally it takes 8 hours to completely fill. How many hours the outlet pipe will take to empty the full tank?
20 hrs
24 hrs
18 hrs
19 hrs
The complete tank is filled in 8 hours, so in 1 hour = 1/8th tank will be filled
Due to outlet pipe in 1 hour = 1/12th part will be filled
Part of the tank emptied in 1 hour = 1/8 – 1/12 = 1/24
Therefore the tank will be emptied in 24 hours.
6. A pipe normally fill a cistern in four hours less than 24 hours. Because of a crack on one side of the cistern the pipe will take 5 hours more to fill. If the cistern is completely filled, in how much time the leakage will completely unfill the cistern?
100 hrs
110 hrs
120 hrs
125 hrs
The cistern is filled in 20 hours
In 1 hour = 1/20th portion of the cistern is filled
Due to crack the cistern is filled in 25 hours
In 1 hour = 1/25th portion of the cistern is filled
Part of the tank emptied in a hour = 1/20 – 1/25 = 1/100
Therefore, the cistern will be completely unfilled in 100 hours.
Correct answer A
7. A tank is 250m in length and 200m in breadth. It is filled through a pipe 0.5m long and 0.4m wide at a speed of 25km/hour. In how much time the water in the tank will reach to 18m level?
110
160
180
140
25 km = 25*1000 = 25000 m
In 1 hour the level of the water will be = 0.5*0.4*25000 = 5000m3
Let us assume that, in x hours the water level will reach to 18m.
Therefore, 5000x = 250×200×18
5000x = 180 hours.
Correct answer C
8. In 40 minutes Pipe R can fill a tanker completely. The same tanker can be filled by Pipe Q 5 times faster than pipe R. In how much time both the pipe together can fill the tanker?
25 minutes
20 minutes
15 minutes
10 minutes
Pipe R fills the tanker in 40 mins
Pipe R will fill the tanker in 1 minute = 1/40th of the tank
Pipe Q fills the tank in 5/40 = 8 minutes
Pipe Q will fill the tanker in 1 minute = 1/8th of the tank
Together they can fill the tanker in a single minute = (1/8) – (1/40) = 1/10th part
Therefore, the tanker will be filled in 10 minutes.
9. There is a leakage in the bottom of the tank. Because of it, the tank will take 7 hours more to 14 hours. Find out the time the leakage will take to completely empty the tank?
30 hrs
22 hrs
42 hrs
Let us assume the leakage will take x hours to empty the tank
Then, 1/x = 1/21 – 1/14
1/x = 1/42
Therefore x = 42 hours.
Correct answer D
10. Pipe A is 4 times faster than Pipe C. Together they can fill a cistern in 42 minutes. Calculate the time taken by slower pipe to alone fill the cistern?
150
200
210
Let us assume the time taken by slower pipe as x
Then, the time taken by faster pipe = x/4 minutes.
Given, 1/x + 4/x = 1/42
5/x = 1/42
x = 210 minutes
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