TCS Coding Question 4 | One programming language has the following keywords that …

11 comments on “TCS Coding Question 4 | One programming language has the following keywords that …”

• 
  

  Gyanendra

  import java.util.*;
  public class Main
  {
  public static void main(String[] args) {
  Scanner scn=new Scanner(System.in);
  String str=scn.nextLine();
  String[] pstr={“break”,”case”, “continue”, “default”, “defer”, “else”, “for”, “func”, “goto”, “if”, “map”, “range”, “return”, “struct”, “type”, “var”};

  for(int i=0;i<pstr.length;i++){
  String check=pstr[i];

  if(str.equals(check)){
  System.out.println(str+" is a keyword");
  return;
  }
  }

  System.out.println(str+" is not Keyword");

  }
  }

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• 
  

  Abhishek

  import java.util.*;

  public class Main{

  public static void main(String agrs[])
  {
  ArrayList str = new ArrayList();
  str.add(“break”);
  str.add(“case”);
  str.add(“contiune”);
  str.add(“default”);
  str.add(“defer”);
  str.add(“else”);
  str.add(“for”);
  str.add(“func”);
  str.add(“goto”);
  str.add(“if”);
  str.add(“map”);
  str.add(“range”);
  str.add(“return”);
  str.add(“struct”);
  str.add(“type”);
  str.add(“var”);

  int flag =0;
  Scanner scn = new Scanner(System.in);
  String input = scn.nextLine();

  ListIterator listIterator
  = str.listIterator();

  while(listIterator.hasNext())
  {
  String temp = listIterator.next();
  if(temp.equals(input))
  {
  flag =1;
  break;
  }
  }

  if(flag==1)
  {
  System.out.println(input + “is a keyword.”);
  }else {
  System.out.println(input + “is not keyword.”);
  }

  }
  }

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• 
  

  Book

  import java.util.*;

  public class QuestionFour {

  public static void main(String args[]){
  Scanner reader = new Scanner(System.in);
  HashSet keyWords= new HashSet();
  String str[]= {“break”, “case”, “continue”, “default”, “defer”, “else”,”for”, “func”, “goto”,
  “if”, “map”, “range”, “return”, “struct”, “type”, “var”};
  for(String a:str){
  keyWords.add(a);
  }
  String check = reader.nextLine();
  if(keyWords.contains(check)){
  System.out.println(“Keyword”);
  }else{
  System.out.println(“not a keyword”);
  }
  reader.close();
  }
  }

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• 
  

  Debasmita

  import java.util.*;

  class Keyword {
  public static void main(String args[]){
  HashMap input = new HashMap ();
  input.put(“break”,”Keyword”);
  input.put(“case”,”Keyword”);
  input.put(“continue”,”Keyword”);
  input.put(“else”,”dKeywor”);
  input.put(“default”,”Keyword”);
  input.put(“defer”,”Keyword”);
  input.put(“for”,”Keyword”);
  input.put(“func”,”Keyword”);
  input.put(“goto”,”Keyword”);
  input.put(“if”,”Keyword”);
  input.put(“map”,”Keyword”);
  input.put(“range”,”Keyword”);
  input.put(“return”,”Keyword”);
  input.put(“struct”,”Keyword”);
  input.put(“type”,”Keyword”);
  input.put(“var”,”Keyword”);

  String str = new Scanner(System.in).nextLine();

  if((input.get(str)) == “Keyword”)
  {
  System.out.println(“Keyword”);
  }
  else
  System.out.println(“Not a Keyword”);

  }
  }
  //Code in java Using Hashmap

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• 
  

  mekala

  my python code
  l1=[“break”,”case”,”continue”,”default”,”defer”,”else”,”for”,”func”,”goto”,”if”,”map”,”range”,”return”,”struct”,”type”,”var”]
  word=input()
  if word in l1:
  print(word,”is a keyword”)
  else:
  pass

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• 
  

  Jatin

  public class Main {
  public static void main(String args[]) {
  String str = “var” ;
  String[] str1 = new String[]{“break”, “case”, “continue”, “default”, “defer”, “else”, “for”, “func”, “goto”, “if”, “map”, “range”, “return”, “struct”, “type”, “var”};

  for(int i = 0 ;i<str1.length ;i++){
  if(str1[i] == str){
  System.out.print(str + " " + "is a keyword") ;
  return ;
  }

  }

  System.out.print(str + " " + "is not a keyword") ;

  }
  }

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• 
  

  Arun

  #java string matches example
  public static void main(String[] args) {
  Scanner scan = new Scanner(System.in);
  String text = scan.nextLine();
  String val[] = {“break”, “case”, “continue”, “default”, “defer”, “else”,
  “for”, “func”, “goto”, “if”, “map”, “range”, “return”, “struct”, “type”, “var”};
  for(String s : val){
  if(text.matches(s)){
  System.out.println(text+” is a keyword”);
  return;}
  }
  System.out.println(text+” is not a keyword”);
  }

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• 
  

  MCE-EEE-

  import java.util.*;
  class Main{
  public static void main(String args[])
  {
  Scanner sc=new Scanner(System.in);
  int flog=0;
  String input=sc.nextLine();
  String a[]={“break”, “case”, “continue”, “default”, “defer”, “else”,”for”, “func”, “goto”,
  “if”, “map”, “range”, “return”, “struct”, “type”, “var”};
  for(int i=0;i<a.length;i++){
  if(a[i].equals(a)){
  flog=1;}
  }System.out.println(flog==1?a+" is a keyword":" is not a keyword");
  }}

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• 
  

  Yuvraj

  import keyword
  print(“”.join([“Its a keyword” if input() in keyword.kwlist else “No dude its not a keyword”]))

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• 
  

  subhojit

  # Simple Python Code

  import keyword
  k=input()
  if k in keyword.kwlist:
  print(“{} is a keyword”.format(k))
  else:
  print(“{} is not a keyword”.format(k))

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• 
  

  Satya Sai Srija

  lis=[‘break’, ‘case’, ‘continue’, ‘default’, ‘defer’, ‘else’, ‘for’, ‘func’, ‘goto’, ‘if’, ‘map’, ‘range’, ‘return’, ‘struct’, ‘type’, ‘var’]
  key=input()
  if key in lis:
  print(key,”is a keyword”)
  else:
  print(key,’is not a keyword’)

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