Arithmetic Elementary Statistics Quiz-3

Question 1

Time: 00:00:00
Let x be the upper limit of the modal class and y be the class mark of the median class of the following data:



What is the value ( x - y)?

13

13

12.5

12.5

11.8

11.8

10.7

10.7

Question 2

Time: 00:00:00
If the mean of 26 observations is 29, and on adding four more observations, the new mean becomes 32. What is the mean of the last four observations?

32.45

32.45

51.5

51.5

37

37

50.8

50.8

Question 3

Time: 00:00:00
Find the mode of the given set of numbers:-

6,11,5,8,6,8,5,11,8,9,7,11,5,6,8,9,11,8,7,6,9.

8

8

10

10

6

6

5

5

Question 4

Time: 00:00:00
What is the difference between the mean and the median of the given data ?

5,9,8,15,12,9,2,19,21,11

2.3

2.3

1.5

1.5

1.1

1.1

3.5

3.5

Question 5

Time: 00:00:00
If the mode of a data is 12 and the arithmetic mean is 9,the median is______________?

15

15

12

12

10

10

20

20

Question 6

Time: 00:00:00
In 50 numbers 10 are threes,15 are fours,18 are fives and remaining are sixes.if a,b and c respectively represent the mean,mode and median of data,what is the value of a+2b-c?

10

10

12.65

12.65

9.94

9.94

8.34

8.34

Question 7

Time: 00:00:00
If mean of a distribution is 10 and the standard deviation is 4. What is the value of the coefficient of variation?

40%

40%

35%

35%

20%

20%

50%

50%

Question 8

Time: 00:00:00
The salary in rupees of 10 employees in a company per day is 50, 55, 60, 65, 70, 72, 75, 80, 84, 89.
What is the standard deviation in the above data?

13.751

13.751

11.983

11.983

9.432

9.432

5.754

5.754

Question 9

Time: 00:00:00
The algebraic sum of the deviations of a set of n values from their mean is:

Zero

Zero

n - 1

n - 1

1

1

n - 2

n - 2

Question 10

Time: 00:00:00
If ‘X’ is a random variable, taking values ‘x’, probability of success and failure being ‘p’ and ‘q’ respectively and ‘n’ trials being conducted, then what is the probability that ‘X’ takes values ‘x’? Use Binomial Distribution

P(X = x) = nCx px qx

P(X = x) = nCx px qx

P(X = x) = xCn qx p(n-x)

P(X = x) = xCn qx p(n-x)

P(X = x) = nCx px q(n-x)

P(X = x) = nCx px q(n-x)

P(x = x) = xCn pn qx

P(x = x) = xCn pn qx

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