Sumaiya Please explain question 1 again. how the quantity of water in initial mixture is calculated? Log in to Reply
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Lavanya Chowdary In second question we have to calculate the ratio of water and milk in the given mixture. 90:30=3:1 hence,the person can sold the 1/4th of the mixture (1/4*100)=25% 25% of the mixture can contain both milk and water . After he sold the 25% of mixture from that we have to calculate the what percent water and milk can contain the 90ml of mixture. (25/100)*90=22.5 of water can contain in that mixture. (75/100)*90=67.5 of milk can contain in that mixture. Hence , he added the 30L of water (the quantity of milk he sold 25% =30L) into the that. 22.5+30=52.5 then the volume of milk =67.5 Then the ratio is =67.5:52.5 =9:7 Log in to Reply