Divisibility Problems with Solutions Quiz-1

The equation can be facorize as 3*5*3*2*2*2*7*2*5*2*5*5*5 or 2^5*3^2*5^5*7^1 total no of prime factor =(5+1)*(5+1)*(2+1)*(1+1)=216

The least possible value is 3

If any number ends in a two digit number that you know is divisible by 4 (e.g. 24, 04, 08, etc.), then the whole number will be divisible by 4 regardless of what is before the last two digits. Alternatively, one can simply divide the number by 2, and then check the result to find if it is divisible by 2.

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467 x 32 is equal to 14944
467 x 33 is equal to 15441

Write factors of 7936

2*2*2*2*2*2*2*2*31
now make pairs for squares

4*4*4*4*31
you will 31 without pair

just multiply 31 with 7936 to get 246016

The remainder = 16
So, the divisor = 16 × 5 = 80
The quotient is 1/20 of the divisor = 80/20 = 4
For any division, dividend = (divisor × quotient) + remainder
In this case :- (80 × 4) + 16
⇒ 320 + 16
= 336
So, the number is 336.  Answer.


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If the number is divisible by 85 rem=0 then by 17 also there will be 0

44100 is the answer...
.because it is divisible by all Nd a perfect square

for no values of n

The greatest number = H.C.F of (138-63), (228-138), (228-63)
H.C.F of 75, 90, 165 = 15.
15 is the greatest number.