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September 22, 2023
Go through Calendar Questions Page to get all the sample Calendar Questions for Practicing for Competitive Exam. Here you will also get some Formula that’ ll make Calendar Questions Solving easy.
Leap year rule:
Odd days:
Doomsday rule:
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1. If it is Sunday on Jan 1, 2006, determine the day on Jan 1, 2010?
Friday
Monday
Thursday
None of the above
It was Saturday on 31st December 2005.
Odd days from the year 2006 to 2009 = (1+1+2+1) = 5 days
Therefore, it was Thursday on 31st December 2009, and the next day, 1st January 2010 will be Friday.
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2. Find out the day for 28th of May 2006?
sunday
tuesday
saturday
28 May 2006
= (2005 + time from 1st Jan 2006 to 28th May 2006)
Number of odd days in 1600 years =0
Number of odd days in 400 years =0
Calculation for 4 years = (4 ordinary years + 1 leap year)
= (4 x 1 + 1x 2)
= 6 odd days
Also, total days =
Jan = 31
Feb = 28
March = 31
April = 30
May= 28
Sum of all these days = 148
Number of add days in these 148 days = (21 weeks + 1 day) = 1 odd day
Total odd days = 0+0+6+7 = 7 (which leaves no odd day)
Therefore, the required day is Sunday.
3. Find out the day after 61 days if today is Monday?
Tuesday
Saturday
It takes seven days to repeat each day in a week.
Therefore, after 63 days, it will be on Monday.
And after 61 days, it will be on Saturday.
4. If it is Monday on 6th March 2005, what is the day of 6th March 2004?
Sunday
Wednesday
2004 is a leap year and has 2 odd days
The month of Feb 2004 will not be calculated and hence, it has only 1 odd day.
Therefore, the day of 6th March 2005 will be one day after the day on 6th March 2004.
It is also given that 6th March 2005 is a Monday.
Hence, 6th March 2004 is a Sunday.
5. For April 2001, on what all dates will it be Wednesday?
5, 7, 9, 10
2, 3, 5, and 7
4, 11, 18, and 25
1, 2, 3, and 4
Determining the day on 1st April 2001 = (2000 + time from 1.1.2001 to 1.4.2001)
Number of odd days in 1600 years = 0
Number of odd days in 400 years = 0
Calculation for Jan, Feb, March, and April= 31 +28 + 31 +1 = 91 days and 0 odd days
Total odd days = (0+0+0) =0
Day on 1st April 2001 = Sunday
Therefore, dates on which Wednesday will fall = 4, 11, 18, and 25 as counted by the interval of 7 days each.
6. Calculate the number of days in p weeks and p days.
8p
p^2
5 + p
6p
p weeks and p days = (7p + p) days
= 8p days
7. From the options provided, which day is not a century’s last day?
Odd days in 100 years = 5
Therefore, we can say that the last day of the first century is Friday.
Odd days in 200 years = (2 x 5) Ξ 3 odd days
Therefore, the last day of the second century is Wednesday
Odd days in 300 years = (5 x 3) = 15 Ξ 1 odd days
Therefore, we can say that the last day of the third century is Monday.
Odd days in 400 years = 0
Therefore, we can say that the last day of the 3rd centaury is Sunday.
The above cycle is repeated.
We can say that a century’s last day cannot be Tuesday, Thursday, or Saturday.
8. The day of the week on 7th February 2005 was a Monday. Determine the day of the week on 7th February 2004?
2004 is a leap year and hence, number of odd days = 2
Therefore, the day of 8th Feb 2004 will be 2 days before the day on 8th Feb 2005.
Therefore, the day is Saturday.
9. Among the following, which of these is not a leap year?
300
400
1200
The number which is divisible by 400 is a leap year.
Therefore, the year 300 is not a leap year.
10. It is on Friday, 7th December 2007. Which day of the week will fall on 7th December 2006?
2006 is an ordinary year. Hence, the number of odd days = 1.
Also, the day of 7th December 2007 will be one day after the day on 7th December 2006.
Day on 7th December 2007= Friday.
Hence, 8th December 2006 = Thursday.
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