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Get Hiring UpdatesCognizant GenC Elevate Sample Coding Question 2
Question 2
In this article, we will discuss about Coding Question with their solution in java and Python. This question is based on tree data structure in which we have to figure out all the siblings of person X from the data and return the array of all siblings in increasing order.
Question 2
Henry is extremely keen on history and every one of the ages of his family. He does a ton of exploration and understands that he has plummeted from the incomparable Amaya line. After a ton of looking through old records and the most recent records of the general public, he can discover all the parent-kid connections in his family right from the extraordinary ruler Ming of the tradition to himself.
These connections are given in the structure a direct exhibit where emperor is at the main position and his kids are at pos (2i + 1) and (2i + 2)
This is the pattern followed throughout.
Henry needs to sort out every one of the kin of individual X from the information.
Write a program for Henry to figure out all the siblings of person X from the data.
Return the sorted list of all of Henry’s siblings.
If no sibling return {-1}
- input 1: N, the length of the array
- input2: An array representing the ancestral tree
- input 3 : X, the person whose siblings are sought.
- output – return the array of all siblings in increasingly sorted order.
Example 1 :
input 1 : 5
input 2 : {1,2,3,4,5}
input 3 : 1
output : {-1}
Explanation : x is the root of the tree and has no siblings
Example 2 :
input 1 : 6
input 2 : {1,2,3,4,5,6}
input 3 : 5
output : {4,6}
Explanation : {2,3 } are the children of {1}.
{4,5,6 } are the children of {2,3}, thus the siblings of x= 5 are {4,6}
import java.util.*;
public class Main
{
Node root;
static class Node
{
int data;
Node left, right;
Node (int data)
{
this.data = data;
this.left = null;
this.right = null;
}
}
public static void main (String[]args)
{
Main t2 = new Main ();
Scanner sc = new Scanner (System.in);
int length = sc.nextInt ();
int arr[] = new int[length];
for (int i = 0; i < length; i++)
{
arr[i] = sc.nextInt ();
}
int target = sc.nextInt ();
t2.root = t2.insertLevelOrder (arr, t2.root, 0);
Set < Integer > sets = t2.levelOrderBottom (t2.root, target);
sets.remove (target);
System.out.println (sets);
}
public static Node insertLevelOrder (int[]arr, Node root, int i)
{
if (i < arr.length)
{
Node temp = new Node (arr[i]);
root = temp;
root.left = insertLevelOrder (arr, root.left, 2 * i + 1);
root.right = insertLevelOrder (arr, root.right, 2 * i + 2);
}
return root;
}
public Set < Integer > levelOrderBottom (Node root, int target)
{
if (root == null)
{
return null;
}
Queue < Node > q = new LinkedList <> ();
q.offer (root);
while (!q.isEmpty ())
{
int qsize = q.size ();
Set < Integer > temp = new HashSet <> ();
for (int i = 0; i < qsize; i++)
{
Node child = q.poll ();
temp.add (child.data);
if (child.left != null)
{
q.offer (child.left);
}
if (child.right != null)
{
q.offer (child.right);
}
}
if (temp.contains (target))
return temp;
}
return null;
}
}
def identify_siblings(tree_array, x):
tree_len = len(tree_array)
index = tree_array.index(x)
level = 0
start_index = level
number_of_nodes = 0
while start_index < tree_len:
end_index = pow(2, level) + start_index
if x in tree_array[start_index:end_index]:
break
level += 1
start_index = (2 * start_index) + 1
final_array = tree_array[start_index:end_index]
final_array.remove(x)
return final_array if final_array else [-1]
