Deloitte Time & Work Questions and Answers Quiz-1

: 35 days worked together + 21 days abhimayu worked = finished the work 35(1/50) + 21(1/x) = 1

=>X=70 days

15 oxen can eat the grass in a field in 80 days

i.e 1 ox can eat the grass in a field in 1200 days

20 cows can eat the grass in a field in 80 days

i.e 1 cow can eat the grass in a field in 1600 days.

Using units method, we can solve this problem

First, LCM of 1200 and 1600 is 4800

Let 4800 is the total grass of the field.

An ox eats 4 units of grass in the field in a day i.e 4800/1200= 4

A cow eats 3 units of grass in the field in a day i.e 4800/1600= 3

Given that 6 oxen and 2 cows will eat the grass together in the field until it\'s finished.

6 oxen eat 4 units of grass in the field in a day i.e 6*4 units= 24 units/day. 2 cows eat 6 units of grass in the field in a day i.e 2*3 units = 6 units/day.  As 6 oxen and 2 cows eat the grass together in a day, 30 units of grass is consumed per day i.e 24 units per day(by 6 oxen) + 6 units per day(by 2 cows) = 30 units.

Finally, divide the total grass with units of grass consumed per day by the animals(by 6 oxen and 2 cows per day together) i.e 4800/30= 160 days The answer is 160 days

P can do in 5* 8 hours= 40 hours Q can do in = 24 hours Working together in one hour = (1/40) + (1/24) = 1/15 Total work can be finished in 15 hours They 5 hours a day so total number of days = 15/5 = 3 days

10 men's, 1 day work=10/(12*6)=5/36 If 21 women\'s, 1 day work= 21/W ,then 3[(5/36)+(21/W)]= 1 ,On solving, W=108 So, 12 women can complete the work in 108/12=9 days

Take any number of person as your wish .

Eg say 10 .

So , 10 persons can do a piece of work in 12 days. Therefore 1 person = 10x12= 120 days. Two times the no.of persons .So, Now 20 persons . Therefore This much people can complete the full work in 120/20 = 6 days . Then , half of the work can be done in 3 days .

5u=2t

=>u=2t/5

let, x be the number of trained labourers

(33*2t*15*12)/(5*x*t*11*9)=2/3

=>x=(3*12)=36

 

49*13/2*8=196*x*5

x=2.6 days

Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)

1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days

1/3 ---- 6

1 -------? A = 18

R = 1/18 * 60/100 = 1/30

1 ----- 1/30

2/3 ----? => 20 days