DXC Technology Time, Speed and Distance Questions and Answers Quiz-1

Option(C) is correct

Option(D) is correct

Option(A) is correct

Solution:
Option(B) is correct

Let total distance =D=D

Distance travelled at 4 kmph speed =(2/3)D=(2/3)D

Distance travelled at 5 kmph speed =(1−2/3)D=(1/3)D

Total time =1 hr 24 min = (60+24) min =84/60 hr =21/15 hr

We know,  Time=Distance/Speed

Total time

21/15=(2/3)(D/4) + (1/3)(D/5)

=> 21/15=(D/6) + (D/15)

=>21/15=(5D+2D)/30

=>21/15 = 7D/30

=>D = 6

Let both of them meet after T min

4500 m are covered by Suresh in 60 min.

In T min he will cover 4500T/60 m

Likewise, In T min Suresh's wife will cover 3750T/60 m

Given,

(4500T/60)+(3750T/60)=726

=>T=5.28 minutes

Average speed of train leaving Delhi = 200/4=50 km/hr

Average speed of train leaving Ambala cantt. = 200×2/7==400/7

By the time the other train starts from Ambala cantt, the first train had travelled 100 km

Therefore, the trains meet after:

=200−100(50+400/7) = 14/15 hr =(14/15)×60 =56minutes

Hence they meet at 8:56 am

In 1 hour (7 am to 8 am) tarin from station A travels 20 km distance and reaches to C, (say).

A ----------------- C---------------B
7 am --------------------------------- 8 am

AC = 20 km, CB = 90 km

Distance travelled in 1 hour = 20 km

Remaining distance =110−20= 90 km

Time=Distance/Speed =  90/(20+25)=2 hours

So, time = 8 am + 2 am = 10 am

Let the speed of the current be x km/hr

Thus upward speed = (4.5−x) km/hr

and downward speed = (4.5+x) km/hr

Let distance travelled be y, then for the same distance y,

Time Rowing Upwards = 2×Time Rowing Downwards

=>y/(4.5−x)=2×y/(4.5+x)

⇒ x= 1.5 km/hr

Let the total distance travelled by the cart be x ft

Then,

(x/40)−(x/48)=5

⇒(6x−5x)/240=5

⇒ x = 1200 ft