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August 12, 2023
Here, are some easy tips and tricks for you on HP with easy, and efficiently used tricks in competitive and recruitment exams.
Question 1 Find the 8th term in the series \frac{1}{2}, \frac{1}{4}, \frac{1}{6}…….
Options:
A. \frac{1}{20}
B. \frac{1}{14}
C. \frac{1}{16}
D. \frac{1}{18}
Solution: We know that, {a_{n}} = \frac{1}{a+(n-1)d}
Convert the HP series in AP
We get 2, 4, 6,……
In the given series,
a (first term) = 2
d (common difference) = 2 …. (4 – 2)
Therefore, 8th term = t8 = a + (n-1) d
t8 = 2 + (8– 1) 2
t8 = 2 + 7 x 2
t8 = 2 + 14
t8 = 16
Correct option: C
Question 2 Find the Middle term in this Harmonic series 4 , a , 6
A. \frac{22}{5}
B. \frac{21}{5}
C. \frac{23}{5}
D. \frac{24}{5}
we know Inverse of HP is AP.
So, \frac{1}{4} , \frac{1}{a} ,\frac{1}{6} is in AP
a = \frac{24}{5}
Correct option: D
Question 1. Find the harmonic mean (HM) of 8, 9, 6?Options:
A. 4.55
B.6.65
C. 7.56
D. 7.44
Solution: We know that,
H.M = \frac{3abc}{ab + bc + ca}
HM = \frac{3\times 8 \times 9 \times 6}{8\times 9 + 9\times 6 +6\times 8 }
HM = 7.44
Question 2. If Harmonic Mean of two numbers is 8 and one of the number is 12 then Find Another Number.
A. 2B. 4C. 6D. 8
Solution:
We know that,H.M = \frac{2ab}{a+b}Let another number = b
8 = \frac{2\times 12\times b}{12+b}
96 + 8b = 24b
b = \frac{96}{16} = 6
Another number = 6
Question 3. Find the correct option for A, G , H for the elements 4 and 6 . where A is Arithmetic Mean ,G is Geometric Mean & H is Harmonic Mean.
A. A ≥ G ≥ H
B. A < G > H
C. A < G ≥ H
D. A < G < H
Solution Arithmetic mean (A) = \frac{4 +6}{2} = 5
Geometric mean (G) = (4\times 6)^{\frac{1}{2}} = 4.89
Harmonic mean (H) = \frac{2}{( \frac{1}{4} + \frac{1}{6})} = 4.8
Hence it is shown that A ≥ G ≥ H
Correct option: A
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