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September 14, 2023
Highest Common Factor (HCF) of two or more numbers is the greatest number that can divide each number evenly or accurately.On this page you’ll find HCF Question and Answers to practice and improve your concept and understanding of HCF.
There are various methods that are used to find the Highest Common Factor (HCF) and Least Common Multiple (LCM) of numbers. The most common methods that are used to find HCF are :
1. Find the HCF of 777 and 1147?
13
55
24
37
Therefore HCF of 777 and 1147 is 37
Good Job! Did you know? : With $8.5 billion in their kitty, Wipro is the 4th largest Indian IT company in terms of revenue.
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2. What is the HCF of 6851, 9061, 18462?
15
17
20
33
it will show some wrong but explanation is correct
Firstly let's consider any two numbers
Therefore HCF of 6891 and 9061 is 221.
Now consider 221 and the third number 18462. So its HCF is :
221 18462 83
Hence HCF of 221 and 18462 is 17.
3. What is the HCF of 598, 874?
49
47
46
None of the above
Therefore HCF of 598 and 874 is 46
4. what is the HCF of 32712, 4002?
174
175
179
181
32712=4002*8+696
4002=696*5+522
696=522*1+174
522=174*3+0
HCF=174Ans.
5. What is the HCF of 2923, 3239?
74
75
79
81
2923 ) 3239 ( 1
- 2923
316 ) 2923 ( 9
- 2844
79 ) 316 ( 4
- 316
X
HCF is 79Ans.
6. what is the HCF of 42, 63 & 140?
7
5
9
8
42 factors are 2 x 3 x 7
63 factors are 3 x 3 x 7
140 factors are 2 x 7 x 2 x 5
SoHCF is 7Ans
7. Find the HCF of 3/8, 5/12, and 9/14?
HCF 1/168
HCF 2/169
HCF 5/168
None of the Above
: HCF = HCF of 3, 5, and 9
LCM of 8, 12, 14
LCM of 8, 12, 14=
= 1
2*2*2*3*7
=1/168
8. Find the highest number, which divides 590 908 1014 and leaves the same remainder in each case?
150
106
159
57
Since the required number that divides 590 908 1014, leaves the same remainder in each case, which means that number will accurately divide the difference of any two numbers.
So Consequently the required number = HCF (908 - 590), (1014 - 908) and (1014 - 590), In other words it will be the HCF of 318 ,106, 424
318= 2 x 3 x 53
106= 2 x 53
424= 2 x 2 x 2 x 53
HCf is 2 x 53
=106 Ans.
Hence the required number = 106
9. The HCF of two number is 42, and their LCM is 1260. If one of the figures is 210, find the other number?
250
252
256
248
The basic theorem is
The product of two numbers = The outcome of their HCF and LCM
Their LCM= Product of the numbers
HCF of the numbers
Therefore the other number = 42*1260/210= 252
Hence option B is the correct one.
10. Calculate the HCF of 22 and 33
11
12
22 = 2*11
33 = 3*11
So the HCF will be 11
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