HirePro Ratio and Proportion Quiz-1

let the third number be x.
Then, first number = 130% of x = \frac{130x}{100}=\frac{13x}{10}
Second number = 140% of x = \frac{140x}{100}=\frac{7x}{5}
Ratio of first two numbers = \frac{13x}{10}:\frac{7x}{5}=13:14

Let the shares of Ranbir,Ranveer, Alia and Deepika be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 1000
x = 1000.
Therefore, Ranveer's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.

Let the ages of Salman Khan and Shah Ruk Khan be x and y respectively.
According to the equation, (x-6)/(y-6) = 6/5
=> (x+4)/(y+4) = 11/10
After solving we get y = 16

Let electricity bill = 6x , gas bill = 4x and grocery=3x
New electricity bill expenditure= \frac{107}{100} \times 6x = \frac{642x}{100}
New gas bill expenditure = \frac{108}{100} \times 4x = \frac{432x}{100}
New grocery expenditure = \frac{109}{100} \times 3x = \frac{327x}{100}
New ratio = \frac{642x}{100} : \frac{432x}{100} : \frac{327x}{100} = 214:144:109

Let the number of 25p coins = x
Number of 50p coins = 600 - x
x \times \frac{25}{100} + (600-x)\times \frac{50}{100} = Rs.\ 200

Solving this, we get x = 400

25p coins are = 400

Let Karan and Arjun’s present ages be x and y respectively

According to the question,
3 years ago, their ages were (x-3) and (y-3) respectively.
3 years hence, their ages will be (x+3) and (y+3) respectively.

The two equations produced are:

\frac{x-3}{y-3}=\frac{2}{3}
\frac{x+3}{y+3}=\frac{5}{6}

Solving these equations,we get
x=7 years
y=9 years

Circumference of square = 4 x side of square = 88m
Side of square = 22m
Circumference of circle = 2\prod x radius of circle = 80m
Radius of circle = 14
Area of square = 22 x 22 = 484
Then, Area of square : Radius of circle = 484 : 14 = 242 : 7

Savings = Income - Expenditure
Let Incomes be x and Expenditures be y.

15,000 = 3x - 4y
20,000 = 5x - 7y

Solving these equations, we get x= 25,000 , y= 15,000

Anuv’s monthly income = 3x = 75,000
Ashneer’s monthly income = 5x = 125,000

Difference = 125,000 - 75,000 = 50,000

a = 2x
b = 5x
c = 7x

b + c - a = 5x + 7x - 2x = 10x
a = 2x

(b+c-a) : a = 10x : 2x = 5 : 1

The savings of Chetan and Dinesh are 3x – 5y and 4x – 7y respectively.
3x – 5y = 200 --- (1)
4x – 7y = 200 --- (2)
Multiplying (1) by 7 and (2) by 5 and subtracting the resultant equation (2) from resultant equation (1), we get x = 400.
The incomes of Chetan and Dinesh are 3x = Rs.1200 and 4x = Rs.1600 respectively.