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Home > HSBC Placement Papers and Previous Years Papers 2022 PDF > HSBC Aptitude Question and Answers 2022 PDF
Topics
9-10
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15 Mins
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Quant is the first section
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Click on Topics below to practice previous year HSBC questions
1. A boatman goes 2 km against the current of the stream in 2 hour and goes 1 km along the current in 20 minutes. How long will it take to go 5 km in stationary water?
4 hr
2 hr 30 min
2 hr
1 hr 15 min
Speed upstream = 2/2=1 km/hr
Speed downstream = 1/(20/60)=3 km/hr
Speed in still water = 1/2(3+1)=2 km/hr
Time taken to travel 5 km in still water =5/2= 2 hour 30 minutes
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2. Find the missing number
279936, 46656, 7776, 1296
66
36
60
46
279936÷6=46656
46656÷6=7776
7776÷6=1296
1296÷6=216
216÷6=36
3. The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 9000, brokerage being 1⁄4 %, is:
Rs. 125.25
Rs. 124.75
Rs. 112.20
Rs. 108.25
Assume that face value = Rs.100
Dividend per share = Rs.10.5 (as it is 10.5% stock)
By investing Rs.9000, earnings = Rs.756
To get an earning of Rs.10.5, investment required = 9000×10.5756
=Rs.125
ie,market value of Rs. 100 stock = Rs.(125- 1/4) = Rs.124.75
4. 9 examiners can examine a certain number of answer books in 12 days by working 5 hours a day. How many hours in a day should 4 examiners work to examine twice the number of answer books in 30 days?
9
11
12
10
Given that work done by 9 examiners in 12 days by working 5 hours a day = 1 => Work done by 1 examiner in 1 day in 1 hour =1/(9×12×5).. (Equation 1)
Work needs to be done by 4 examiners in 30 days working x hours a day = 2 (∵ twice work to be completed) => Work needs to be done by 1 examiner in 1 day working x hours a day =2/(4×30)... (Equation 2)
From (Equation 1) and (Equation 2), x=(2/(4×30)) / (1/(19×12×5)) = 9
5. if log102 = 0.3010, what is the value of log101600 ?
None of these
5.204
3.204
1.204
log101600 = log10(16 × 100) = log10(16) + log10(100) = log10(24) + log10(102) = 4 log10(2) + 2 = (4 × 0.3010) + 2 = 1.204 + 2 = 3.204
6. A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
5,7
4,8
6,6
7,4
Let x and (12−x) litres of milk be mixed from the first and second container respectively.
Amount of milk in x litres of the the first container =.75x Amount of water in x litres of the the first container =.25x
Amount of milk in (12−x) litres of the the second container =.5(12−x) Amount of water in (12−x) litres of the the second container =.5(12−x)
Ratio of water to milk =[.25x+.5(12−x)]:[.75x+.5(12−x)= 3:5
(.25x+6−.5x) / (.75x+6−.5x)= 3/5
⇒(6−.25x) / (.25x+6)=3/5
⇒30−1.25x =.75x+18
⇒2x=12
⇒x=6 Since x=6, 12−x=12−6=6
Hence 6 and 6 litres of milk should mixed from the first and second container respectively.
7. A company has 10 software engineers and 6 civil engineers. In how many ways can they be seated around a round table so that all the civil engineers are together?
(10!)2
11! × 6!
10! × 6!
9! × 6!
Group all the 6 civil engineers and consider as a single civil engineer. Hence, we can take total number of engineers as 11. These 11 engineers can be arranged around a round table in (11−1)!=10 ways ...(A)
We had grouped 6 civil engineers. These 6 civil engineers can be arranged among themselves in 6 ways ...(B)
From (A) and (B), required number of ways =10!×6!
8. How many minimum terms in the G.P.: 1, 1.2, 1.44, 1.728, . . . are needed so that the sum of the terms is greater than 25? (Take log 2 = 0.301, log 3 = 0.4771
8
13
The given GP is 1, 1.2, 1.44, 1.728, ----- Here a = 1, r = 1.2 Now Sn = > 25 ⇒ > 25 ⇒ 1.2n - 1 > 5 ⇒ 1.2n> 6 ⇒ n log (1.2) > log 6 ⇒ n[log12 – log10] > log 6 ⇒ n [2 log 2 + log 3 – log 10) > log 2 + log 3 ⇒ n [2 × 0.301 + 0.4771 – 1) > 0.301 + 0.4771 ⇒ 0.07491 n > 0.7781 ⇒ = 9.83 ⇒ n > 9.83 So the least value of n is 10
9. A merchant has three different types of milk- 324 litres, 351 litres and 459 litres. Find the minimum number of casks of equal size that can store the milk without mixing.
17
61
42
51
Since a minimum number of casks are required, the size of the cask is greatest. Also the cask in three cases is of equal size. The size of the cask is the H.C.F. of 324 litres, 351 litres and 459 litres which is 27. Now, the number of casks required for storing the milk = (324 + 351+ 459)÷ 27 = 42.
10. Train A leaves Mumbai for Pune at 5:30 a.m. and reaches Pune at 9:30 a.m. Train B leaves Pune for Mumbai at 7:30 a.m. and reaches Mumbai at 13:30 hrs. At what time will these two trains meet?
7:42 a.m.
8:42 a.m.
9:12 a.m.
8:48 a.m.
Train A takes 4 hrs to complete its journey and train B takes 6 hrs to complete its journey. Let the total journey = D. Speed of train A = D/4 and speed of train B = D/6.
Distance covered by train A in 2 hrs = D/4 × 2 = D/2. ∴ Remaining distance = D/2
∴ time taken to meet = D/2 / ((D/4)+(D/6))= 6/5 hours= 1 hr 12 min. ∴ Trains will meet at 7.30 + 1 hr 12 min. = 8.42 A.M.
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March 22, 2022