Don’t worry, unlock all articles / blogs on PrepInsta by just simply logging in on our website
Type atleast 3 characters
Popular Searches
Trending Pages
Notifications Mark All Read
Test Notification
Walmart is Hiring for 2024 and 2025! Batches Click here to apply!
PREPINSTA PRIME BIG BILLION SALE is live now. Go and grab the amazing offer.
asdasd
You have purchased Zoho Prime Mock Materials go to My Orders
You have purchased CTS Prime Mock Material. go to My Orders
Data Interpretation Menu9>
PREPINSTA PRIME
Get Hiring Updates right in your inbox from PrepInsta
September 9, 2023
This page consists of LCM Formulas its Definition and Methods to calculate LCM. LCM stands for Least Common Multiple or Lowest Common Multiple. The Lowest Common Multiple is the smallest positive integer that is evenly divisible by both two or more integers.
Question : In annual examination of G.D. goenka school, a question was asked from maths topic as follows: The least number, which when divided by 12, 15, 20 or 54 leaves a remainder of 4 in each case, is :
A. 450B. 454C. 540D. 544
Solution:
LCM of 15, 12, 20, 54 = 540Then number = 540 + 4 = 544[4 being remainder]
Question : Akbar, Birbal, Chanakya start running at the same time and at the same point in the same direction in a circular stadium. Akbar completes a round in 252 seconds, Birbal in 308 seconds and Chanakya in 198 seconds. After what time will they meet again at the starting point ?
A. 26 minutes 18 secondsB. 42 minutes 36 seconds C. 45 minutes D. 46 minutes 12 seconds
Solution :
Required time = LCM of 252, 308 and 198 secondsLCM = 2 \times 2 \times 7 \times9 \times11 = 2772 seconds= 46 minutes 12 seconds
Question : Find the greatest number of four digits which, when divided by 15, 19, 21, and 28, leaves remainders of 8, 2, 16, and 12, respectively.
A. 3521B. 3536C. 3532D. 3569
To find the required number, we need to find the greatest four-digit number that is divisible bythe LCM of 15, 19, 21, and 28 is 3,570.Subtracting the sum of remainders from the result: 3,570 – 38 = 3,532.
Question : Let the least number of six digits which when divided by 4, 6, 10, 15 leaves in each case same remainder 2 be N. The sum of digits in N is :
A. 3 B. 5 C. 4D. 6
LCM of 4, 6, 10, 15 = 60Least number of 6 digits = 100000Dividing 100000 by 60 get we get 40The least number of 6 digits which is exactly divisible by 60 = 100000 + (60 – 40)= 100020 \therefore Required number (N)= 100020 + 2 = 100022Hence, the sum of digits = 1 + 0+ 0 + 0 + 2 + 2 = 5
Question : Find that least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?
A. 2520 B. 1260C. 630D. 196
The LCM of 12, 18, 21, 30LCM = 2 \times 3 \times 2 \times 3 \times 7 \times 5 = 1260 \therefore The required number = 1260/2 = 630
Get PrepInsta Prime & get Access to all 200+ courses offered by PrepInsta in One Subscription
Courses like AI/ML, Cloud Computing, Ethical Hacking, C, C++, Java, Python, DSA (All Languages), Competitive Coding (All Languages), TCS, Infosys, Wipro, Amazon, DBMS, SQL and others
Login/Signup to comment