Quiz-1

He walks towards north for 10 km and then return back by 6 km.
So he reaches the point 4 km north from his position.
Then he walks 3 km towards east.
Applying pythagoras principle,
His current position = √(4² + 3²)
= 5 km (North-East)

The man firstly faces the direction west.
On moving 45 degree clockwise, he faces the direction North-west.
Now again he moved 180 degrees clockwise, now he will be facing South-east.
From here, he moved 270 degree anticlockwise
∴ Finally he is facing towards Southwest.

Note: [Please check carefully always if clockwise or anticlockwise]

Namita walks 14 meters towards west from starting point S.
(Assume the starting point is S).
Then she turns to her right and walks 14 meters.
And then turns to her left and walks 10 meters.
Again turning to her left she walks 14 meters.
i.e. She has gone towards north for 14 meters but return back in south too with the same 14 meters.
So, technically she hasn't covered any distance towards north.

Required answer: 10 + 14 = 24m

After carefully drawing her road map, we'll find that initially the ant moved 10 cm towards east but later a distance of 3 cm and 7 cm successively towards west.
So, her lateral movement is 0.

She moved 3 cm and 2 cm towards south.
So her distance is 5 cm towards south.

From the adjoined figure, it can be seen that the person will cross point B.

Distance = \sqrt{7^{2}+5^{2}}=\sqrt{74} = 8.6 m in south-east

Point P will be in the east direction from F at a distance of 6 m.

From here, we can conclude that the bus needs to travel 5 km towards south.

Distance between final point to initial point = \sqrt{6^{2}+8^{2}}=\sqrt{100} = 10 km.