Wipro WILP Divisibility Quiz- 1

Given that : 2/3^rd of the oranges are not edible out of 3,75,569

no. of edible oranges= 2/3 x 3,75,569

= 2,50,379

=  3,75,569 - 2,50,379

= 1,25,189

Similarly no. of edible apples = 3/5^th x 2,45,589

=1,47,353

=2,45,589 - 1,47,353

= 98,236

 

Total nouber of fruits which the owner can sell =  1,25,189 +  98,236

= 2,23,425

 

n divided by 8 yields a remainder equal to 3 is written as follows

n = 8 k + 3 , where k is an integer.

add 5 to both sides of the above equation to obtain

n + 5 = 8 k + 8 = 8(k + 1)

The above suggests that n + 5 divided by 8 yields a remainder equal to zero.

Video solution:

Let the three consecutive numbers be n-3, n, and n+3. So
n+n+1+n+2 = 51,
3n+3 = 51,
n = 16.
Thus the largest among them is n+2 = 18

X=4x+2
Y=4y+1
X+Y=4(x+y)+3
X+Y=4(x-y)-4+4+3 [by adding -4 and +4]
X+Y=4(x+y-1)+7
As seen above, if we divide X+Y by 4, the remainder will be 7.

The given number = 526897

52689-14= 52675

5267-10=5257

575-14=561

56-2=54

which is not divisible by 7

LCM of 25, 70 and 35 is 350

Now 350 = 5 x 7 x 2 x 5

To make it perfect square, it must be multiplied from 2 x 7.

So required no. = 5 x 5 x 7 x 7 x 2 x 2 = 4900

The simple answer of your question is 3 and 9.

Step-by-step explanation:

Hey Mate,

The simple answer of your question is 3 and 9.

For example,

Take any randomly 5 digit number , we take 12345.

so,

12345 - (1+2+3+4+5)

=> 12330

12330 is a multiple of 9 and 3 both.

Lets we take another example.

We take 11111

so,

11111 - (1+1+1+1+1)

=> 11106

11106 is a multiple of 9 and 3.

 

we just need to find the remainder when 21549876 is divided by 46

the remainder will be 26 after dividing 21549876 by 46

hence 26 is the least number which should be added to 21549876 to make it completely divisible by 46

L.C.M of 2,3 and 5 is 30

so on dividing the largestt 7 digit number i.e: 9999999 by 30 we get a remainder 9

So largest number which is divisible by 2,3 and 5 is 9999999-9= 9999990

For any number to be co prime with 51 it should not be a multiple of 3 and 17

Number of integers less than 1,00,000 which are multiples of 3 = floor(1,00,000/3) = 33,333

Number of integers less than 1,00,000 which are multiples of 17 = floor(1,00,000/17) = 5882

Number of integers less than 1,00,000 which are multiples of 51 = floor(1,00,000/51) = 1960

Number of integers less than 1,00,000 which are multiples of 3 or 17 = 33333 + 5882 - 1960 = 37,255

Number of integers less than 1,00,000 which are not multiples of 3 or 17 = 1,00,000 - 37,255 = 62,745